The point (1, -3, 4) lies in the octant: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a three-dimensional Cartesian coordinate system,the octants are determined by the signs of the coordinates $(x, y, z)$.For the point $(1, -3, 4

Vedclass · Accepted Answer

Fourth

Vedclass · Answer

(C) In a three-dimensional Cartesian coordinate system,the octants are determined by the signs of the coordinates $(x, y, z)$.For the point $(1, -3, 4)$,we have $x > 0$,$y  0$.The octants are defined as follows:$I: (+, +, +)$$II: (-, +, +)$$III: (-, -, +)$$IV: (+, -, +)$$V: (+, +, -)$$VI: (-, +, -)$$VII: (-, -, -)$$VIII: (+, -, -)$Since the signs are $(+, -, +)$,the point $(1, -3, 4)$ lies in the $IV$ octant.

The point $(1, -3, 4)$ lies in the octant:

Similar Questions

The distance between the points $(1, 3, 2)$ and $(2, 1, 3)$ is:

If $d_1, d_2, d_3$ are the distances of the point $(1, 2, 3)$ from the $X, Y, Z$-coordinate axes respectively,then $2 d_2^2 + d_3^2 + 1 =$

$A$ point $(x, y, z)$ moves parallel to the $x$-axis. Which of the three variables $x, y, z$ remain fixed?

The distance of the point $(1, 2, 3)$ from the $x$-axis is.......

If the sum of the squares of the distances of a point $P(x, y, z)$ from the three co-ordinate axes is $324$,then the distance of point $P$ from the origin is ....

Vedclass Test Series

Exam Paper Generator

Online Exam Module