The points $A(2, 1)$,$B(3, -2)$ and $C(a, b)$ are vertices of the rectangle $ABCD$. If the point $P(3, 4)$ lies on the line $CD$,then $5a + 10b = $

  • A
    $41$
  • B
    $10$
  • C
    $45$
  • D
    $-15$

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