The polarising angle for a transparent medium | vedclass

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Question

(B) According to Brewster's Law,the refractive index $\mu$ of a medium is related to the polarising angle $	heta$ by the equation $\mu = 	an 	heta$

Vedclass · Accepted Answer

$	heta=\cot ^{-1}\left(\frac{v}{c}ight)$

Vedclass · Answer

(B) According to Brewster's Law,the refractive index $\mu$ of a medium is related to the polarising angle $	heta$ by the equation $\mu = 	an 	heta$. By definition,the refractive index $\mu$ is the ratio of the speed of light in air $(c)$ to the speed of light in the medium $(v)$,so $\mu = \frac{c}{v}$. Equating the two expressions for $\mu$,we get $	an 	heta = \frac{c}{v}$. Taking the reciprocal of both sides,we have $\cot 	heta = \frac{1}{	an 	heta} = \frac{v}{c}$. Therefore,the relation is $	heta = \cot ^{-1}\left(\frac{v}{c}ight)$.

The polarising angle for a transparent medium is $\theta$,and $v$ is the speed of light in that medium. Then the relation between $\theta$ and $v$ is (where $c$ is the velocity of light in air).

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