(B) Let the equation of the line be $L(x, y) = 3x - 4y - 8 = 0$. For the point $(3, 4)$,we calculate $L(3, 4) = 3(3) - 4(4) - 8 = 9 - 16 - 8 = -15$. S

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(B) Let the equation of the line be $L(x, y) = 3x - 4y - 8 = 0$. For the point $(3, 4)$,we calculate $L(3, 4) = 3(3) - 4(4) - 8 = 9 - 16 - 8 = -15$. Since $L(3, 4) For the point $(2, -6)$,we calculate $L(2, -6) = 3(2) - 4(-6) - 8 = 6 + 24 - 8 = 22$. Since $L(2, -6) > 0$,the point $(2, -6)$ lies on the other side of the line. Because the values of $L(x, y)$ at these two points have opposite signs,the points lie on different sides of the line.

Class 11 Mathematics Straight Lines Distance between two lines, Perpendicular distance of the line from a point, Position of point w.r.t. line

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The positions of the points $(3, 4)$ and $(2, -6)$ with respect to the line $3x - 4y = 8$ are:

A
On the same side of the line
B
On different sides of the line
C
One point on the line and the other outside the line
D
Both points on the line

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Straight Lines

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Distance between two lines, Perpendicular distance of the line from a point, Position of point w.r.t. line

If $p$ and $q$ are the perpendicular distances from the origin to the straight lines $x \sec \theta - y \operatorname{cosec} \theta = a$ and $x \cos \theta + y \sin \theta = a \cos 2 \theta$,then

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On which side of the line $7x + 5y - 9 = 0$ do the points $(3, 4)$ and $(-9, 6)$ lie?

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The distance of point $(-2, 3)$ from the line $x - y - 5 = 0$ is

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The points on the $x$-axis whose perpendicular distance from the line $\frac{x}{a} + \frac{y}{b} = 1$ is $a$ are

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Two points $A$ and $B$ have coordinates $(1, 1)$ and $(3, -2)$ respectively. The coordinates of a point $P$ at a distance of $\sqrt{85}$ from $B$ on the line through $B$ perpendicular to $AB$ are:

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The positions of the points $(3, 4)$ and $(2, -6)$ with respect to the line $3x - 4y = 8$ are:

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If $p$ and $q$ are the perpendicular distances from the origin to the straight lines $x \sec \theta - y \operatorname{cosec} \theta = a$ and $x \cos \theta + y \sin \theta = a \cos 2 \theta$,then

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