The post office is to the east of the school, | vedclass

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Question

(C) Let the distance of the house from the school be $x$.According to the problem,the distance of the market from the post office is also $x$.Let the

Vedclass · Accepted Answer

North-east

Vedclass · Answer

(C) Let the distance of the house from the school be $x$.According to the problem,the distance of the market from the post office is also $x$.Let the school be at the origin $(0,0)$ on a Cartesian plane.The post office is to the east of the school,so its position is $(d, 0)$ for some distance $d$.The house is to the south of the school,so its position is $(0, -x)$.The market is to the north of the post office,so its position is $(d, x)$.To find the direction of the market with respect to the school,we look at the coordinates $(d, x)$.Since both $d$ and $x$ are positive,the market lies in the first quadrant relative to the school,which corresponds to the North-east direction.

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