The power consumed when 10 V voltage is appl | vedclass

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(D) For a series combination of $10$ resistors each of $1 \ \Omega$,the equivalent resistance is $R_s = 10 	imes 1 \ \Omega = 10 \ \Omega$.The power

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$0.01$

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(D) For a series combination of $10$ resistors each of $1 \ \Omega$,the equivalent resistance is $R_s = 10 	imes 1 \ \Omega = 10 \ \Omega$.The power consumed in series is $P_s = \frac{V^2}{R_s} = \frac{10^2}{10} = \frac{100}{10} = 10 \ W$.For a parallel combination of $10$ resistors each of $1 \ \Omega$,the equivalent resistance is $R_p = \frac{1}{10} \ \Omega = 0.1 \ \Omega$.The power consumed in parallel is $P_p = \frac{V^2}{R_p} = \frac{10^2}{0.1} = \frac{100}{0.1} = 1000 \ W$.Therefore,the ratio is $\frac{P_s}{P_p} = \frac{10}{1000} = 0.01$.

The power consumed when $10 \ V$ voltage is applied to a series combination of $10$ resistors of each $1 \ \Omega$ is $P_{s}$ and the power consumed when the same $10 \ V$ is applied to the parallel combination of these $10$ resistors is $P_p$. The value of $\frac{P_{s}}{P_{p}}$ is

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