The principal organic product formed in the f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of an alkene with $HBr$ in the presence of a peroxide follows the anti-Markovnikov addition mechanism (Kharasch effect or peroxide ef

Vedclass · Accepted Answer

$BrCH_2CH_2(CH_2)_8COOH$

Vedclass · Answer

(C) The reaction of an alkene with $HBr$ in the presence of a peroxide follows the anti-Markovnikov addition mechanism (Kharasch effect or peroxide effect).In this reaction,the $Br^\bullet$ radical adds to the carbon atom of the double bond that has more hydrogen atoms,resulting in the formation of the less substituted radical.For the reactant $CH_2=CH(CH_2)_8COOH$,the terminal carbon $(CH_2=)$ has two hydrogen atoms,while the internal carbon $(-CH=)$ has one.Therefore,the $Br$ atom attaches to the terminal $CH_2$ group,and the $H$ atom attaches to the internal $CH$ group.The product formed is $BrCH_2CH_2(CH_2)_8COOH$.

The principal organic product formed in the following reaction is
$CH_2=CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}}$

Similar Questions

The presence of unsaturation in organic compounds can be tested with

Which of the following is the most stable?

Product $B$ may be :

The reaction of an alkene $X$ with bromine produces a compound $Y$,which has $22.22 \% \ C$,$3.71 \% \ H$ and $74.07 \% \ Br$. The ozonolysis of alkene $X$ gives only one product. The alkene $X$ is,
[Given,atomic mass of $C = 12$; $H = 1$; $Br = 80$ ]

Peroxide effect is observed with the addition of $HBr$ but not with the addition of $HI$ to unsymmetrical alkene because

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The principal organic product formed in the following reaction is$CH_2=CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}}$