The probabilities of a student getting I, II | vedclass

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(D) Let $A, B, C$ be the events of getting $I, II$ and $III$ division respectively,and $D$ be the event of failing the examination.Since these events

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) Let $A, B, C$ be the events of getting $I, II$ and $III$ division respectively,and $D$ be the event of failing the examination.Since these events are mutually exclusive and exhaustive,the sum of their probabilities must be $1$.$P(A) = \frac{1}{10} = 0.1$$P(B) = \frac{3}{5} = 0.6$$P(C) = \frac{1}{4} = 0.25$$P(A) + P(B) + P(C) + P(D) = 1$$0.1 + 0.6 + 0.25 + P(D) = 1$$0.95 + P(D) = 1$$P(D) = 1 - 0.95 = 0.05$$P(D) = \frac{5}{100} = \frac{1}{20}$Since $\frac{1}{20}$ is not among the given options,the correct answer is "None of these".

The probabilities of a student getting $I, II$ and $III$ division in an examination are respectively $\frac{1}{10}, \frac{3}{5}$ and $\frac{1}{4}$. The probability that the student fails in the examination is

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