The probability of getting a total of 5 or 6 | vedclass

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(B) The total number of possible outcomes when throwing $2$ dice is $6 	imes 6 = 36$.The outcomes resulting in a sum of $5$ are $(1, 4), (2, 3), (3,

Vedclass · Accepted Answer

$\frac{1}{4}$

Vedclass · Answer

(B) The total number of possible outcomes when throwing $2$ dice is $6 	imes 6 = 36$.The outcomes resulting in a sum of $5$ are $(1, 4), (2, 3), (3, 2), (4, 1)$,which are $4$ cases.The outcomes resulting in a sum of $6$ are $(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)$,which are $5$ cases.The total number of favourable outcomes is $4 + 5 = 9$.Therefore,the required probability is $\frac{9}{36} = \frac{1}{4}$.

The probability of getting a total of $5$ or $6$ in a single throw of $2$ dice is

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