The product X is[Image: 1-chloro-1-(2-chloroe | vedclass

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(B) The reaction involves the substitution of a chlorine atom with a bromine atom using $LiBr$ in $DMSO$ under $S_N2$ conditions.$S_N2$ reactions are

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(B) The reaction involves the substitution of a chlorine atom with a bromine atom using $LiBr$ in $DMSO$ under $S_N2$ conditions.$S_N2$ reactions are highly sensitive to steric hindrance.In the given molecule,there are two chlorine atoms: one is a tertiary chloride (at the $1$-position of the cyclopentane ring) and the other is a primary chloride (at the end of the ethyl chain).$S_N2$ reactions occur much faster at less sterically hindered sites.Therefore,the primary chloride is significantly more reactive towards $S_N2$ substitution than the tertiary chloride.The bromine nucleophile $(Br^-)$ will selectively attack the primary carbon,replacing the primary chlorine atom.The major product is $1$-chloro-$1$-($2$-bromoethyl)cyclopentane.Thus,the correct option is $(B)$.

The product $X$ is
[Image: $1-$chloro$-1-$($2$-chloroethyl)cyclopentane] $\xrightarrow{LiBr/DMSO, S_N2 \text{ conditions}}$ Major product $(X)$

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The product $X$ is[Image: $1-$chloro$-1-$($2$-chloroethyl)cyclopentane] $\xrightarrow{LiBr/DMSO, S_N2 \text{ conditions}}$ Major product $(X)$