The product P in the following reaction is:Ph | vedclass

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(A) The given reaction is a variation of the Perkin condensation.In this reaction, an aromatic aldehyde $(PhCHO)$ reacts with an acid anhydride $((CH_

Vedclass · Accepted Answer

$Ph-CH=C(CH_3)-COOH$

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(A) The given reaction is a variation of the Perkin condensation.In this reaction, an aromatic aldehyde $(PhCHO)$ reacts with an acid anhydride $((CH_3CH_2CO)_2O)$ in the presence of the sodium salt of the corresponding acid $(CH_3CH_2COONa)$.The $\alpha$-hydrogen of the anhydride is abstracted by the base to form a carbanion, which then attacks the carbonyl carbon of the aldehyde.Following dehydration and hydrolysis, the final product is an $\alpha,\beta$-unsaturated carboxylic acid.For the reactants $PhCHO$ and propionic anhydride $((CH_3CH_2CO)_2O)$, the product formed is $Ph-CH=C(CH_3)-COOH$ ($2$-methyl$-3-$phenylprop$-2-$enoic acid).

The product $P$ in the following reaction is:
$PhCHO + (CH_3CH_2CO)_2O \xrightarrow{CH_3CH_2COONa \text{ (anhydrous)}} P$

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The product $P$ in the following reaction is:$PhCHO + (CH_3CH_2CO)_2O \xrightarrow{CH_3CH_2COONa \text{ (anhydrous)}} P$