The product of any four consecutive positive | vedclass

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Question

(C) Let the four consecutive positive integers be $n, (n+1), (n+2),$ and $(n+3)$.The product is $P = n(n+1)(n+2)(n+3)$.We know that the product of $k$

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(C) Let the four consecutive positive integers be $n, (n+1), (n+2),$ and $(n+3)$.The product is $P = n(n+1)(n+2)(n+3)$.We know that the product of $k$ consecutive integers is always divisible by $k!$ (k factorial).Here,$k = 4$,so the product is divisible by $4!$.$4! = 4 	imes 3 	imes 2 	imes 1 = 24$.Therefore,the product of any four consecutive positive integers is always divisible by $24$.

The product of any four consecutive positive integers is always divisible by:

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