The product of one-third of a number and 150 | vedclass

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(D) Let the two numbers be $x$ and $y$.The product of the given numbers is $P_1 = x 	imes y = xy$.According to the problem,the first number is $\frac

Vedclass · Accepted Answer

$50$

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(D) Let the two numbers be $x$ and $y$.The product of the given numbers is $P_1 = x 	imes y = xy$.According to the problem,the first number is $\frac{1}{3}x$ and the second number is $150 \%$ of $y$,which is $\frac{150}{100}y = 1.5y = \frac{3}{2}y$.The product of these two values is $P_2 = (\frac{1}{3}x) 	imes (\frac{3}{2}y) = \frac{1 	imes 3}{3 	imes 2}xy = \frac{1}{2}xy = 0.5xy$.To find what percent $P_2$ is of $P_1$,we calculate: $	ext{Percentage} = (\frac{P_2}{P_1}) 	imes 100$.$	ext{Percentage} = (\frac{0.5xy}{xy}) 	imes 100 = 0.5 	imes 100 = 50 \%$.

The product of one-third of a number and $150 \%$ of another number is what percent of the product of the given numbers?

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