The product of three consecutive even numbers | vedclass

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Question

(A) Let the three consecutive even numbers be $2x, 2x+2$,and $2x+4$.Then,$(2x)(2x+2)(2x+4) = 4032$ $...(1)$Given that the product of the first and the

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(A) Let the three consecutive even numbers be $2x, 2x+2$,and $2x+4$.Then,$(2x)(2x+2)(2x+4) = 4032$ $...(1)$Given that the product of the first and the third number is $252$,we have:$(2x)(2x+4) = 252$ $...(2)$Substituting the value from equation $(2)$ into equation $(1)$:$(2x+2) 	imes 252 = 4032$$2x+2 = \frac{4032}{252} = 16$$2x = 16 - 2 = 14$Thus,the second number is $2x+2 = 16$.Five times the second number is $5 	imes 16 = 80$.

The product of three consecutive even numbers is $4032$. The product of the first and the third number is $252$. What is five times the second number?

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$(\sqrt{4489}-\sqrt{2601})=(?)^{2}$

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