6 frac{1}{15}-4 frac{1}{12}+7 frac{1}{3}-2 fr | vedclass

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(A) To solve the expression $6 \frac{1}{15}-4 \frac{1}{12}+7 \frac{1}{3}-2 \frac{1}{6}$,we separate the whole numbers and the fractions.First,group th

Vedclass · Accepted Answer

$7 \frac{3}{20}$

Vedclass · Answer

(A) To solve the expression $6 \frac{1}{15}-4 \frac{1}{12}+7 \frac{1}{3}-2 \frac{1}{6}$,we separate the whole numbers and the fractions.First,group the whole numbers: $(6 - 4 + 7 - 2) = 7$.Next,group the fractions: $\left(\frac{1}{15} - \frac{1}{12} + \frac{1}{3} - \frac{1}{6}ight)$.The least common multiple $(LCM)$ of the denominators $15, 12, 3, 6$ is $60$.Converting the fractions to have a common denominator of $60$:$\frac{1 	imes 4}{60} - \frac{1 	imes 5}{60} + \frac{1 	imes 20}{60} - \frac{1 	imes 10}{60} = \frac{4 - 5 + 20 - 10}{60} = \frac{9}{60}$.Simplifying the fraction $\frac{9}{60}$ by dividing both numerator and denominator by $3$,we get $\frac{3}{20}$.Combining the whole number and the fraction,we get $7 + \frac{3}{20} = 7 \frac{3}{20}$.

$6 \frac{1}{15}-4 \frac{1}{12}+7 \frac{1}{3}-2 \frac{1}{6}=?$

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