Three times the first of three consecutive odd integers is $3$ more than twice the third. The third integer is

$4767$ exactly divides $xxx\,341$. The missing digits are:

The digits indicated by $^*$ in $3422213^{**}$ so that this number is divisible by $99$ are

$499.99 + 1999 \div 39.99 \times 50.01 = ?$

$6 \frac{1}{15}-4 \frac{1}{12}+7 \frac{1}{3}-2 \frac{1}{6}=?$

Two numbers,when divided by a certain divisor,leave remainders $43$ and $37$ respectively. When their sum is divided by the same divisor,the remainder is $13$. Find the divisor.