The product of two numbers is 120. The sum of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the two numbers be $a$ and $b$.Given that the product of the numbers is $ab = 120$.Given that the sum of their squares is $a^2 + b^2 = 289$.We

Vedclass · Accepted Answer

$23$

Vedclass · Answer

(B) Let the two numbers be $a$ and $b$.Given that the product of the numbers is $ab = 120$.Given that the sum of their squares is $a^2 + b^2 = 289$.We know the algebraic identity: $(a + b)^2 = a^2 + b^2 + 2ab$.Substituting the given values into the identity:$(a + b)^2 = 289 + 2(120)$.$(a + b)^2 = 289 + 240$.$(a + b)^2 = 529$.Taking the square root on both sides,we get $a + b = \sqrt{529} = 23$.Thus,the sum of the two numbers is $23$.

The product of two numbers is $120$. The sum of their squares is $289$. The sum of the two numbers is

Similar Questions

The sum of squares of two numbers is $68$ and the square of their difference is $36$. The product of the two numbers is

$\sqrt{?} \%$ of $160 = 128 \div 4$

If $\frac{x}{y} = \frac{3}{4}$,then the value of $\left(\frac{6}{7} + \frac{y-x}{y+x}\right)$ equals:

The sum of the first $45$ natural numbers is:

$(0.25)^{6} \div (0.125)^{2} \times (0.5)^{4} = (0.5)^{?+3}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module