The r.m.s. velocity of a gas at a certain temperature is $\sqrt{2}$ times that of the oxygen molecules at the same temperature. The gas can be:

The rms speed of an oxygen molecule at a certain absolute temperature is $v$. If the absolute temperature is doubled and the oxygen molecules dissociate into atomic oxygen,then the rms speed would be

$A$ certain amount of an ideal gas is taken from its initial state $1$ to final state $4$ through the path $1 \rightarrow 2 \rightarrow 3 \rightarrow 4$ as shown in the figure. $AB, CD, EF$ are all isotherms. If $v_p$ is the most probable speed of the molecules, then:

By what factor will the $r.m.s.$ velocity change if the temperature is raised from $27^\circ C$ to $327^\circ C$?

Define absolute temperature.

$N$ molecules each of mass $m$ of gas $A$ and $2N$ molecules each of mass $2m$ of gas $B$ are contained in a vessel which is maintained at temperature $T$. The mean square velocity of the molecules of gas $B$ is denoted by $V_2^2$ and the mean square of the $X$-component velocity of the molecules of gas $A$ is denoted by $V_1^2$, then $\frac{V_1}{V_2}$ is