(C) According to Wien's Displacement Law,the product of the wavelength at which the spectral energy density is maximum $(\lambda_m)$ and the absolute

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(C) According to Wien's Displacement Law,the product of the wavelength at which the spectral energy density is maximum $(\lambda_m)$ and the absolute temperature $(T)$ is a constant.$\lambda_m T = \text{constant}$Given that at temperature $T$,the maximum is at $\lambda_0$,we have:$\lambda_0 T = \lambda' (2T)$Solving for $\lambda'$,we get:$\lambda' = \frac{\lambda_0 T}{2T} = \frac{\lambda_0}{2}$Therefore,at temperature $2T$,the maximum will be at $\lambda_0/2$.

Class 11 Physics 2 Thermal Properties of Matter: Heat Transfer Spectral Emissive Power and Wien's Displacement Law

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The radiation energy density per unit wavelength at a temperature $T$ has a maximum at a wavelength $\lambda_0$. At temperature $2T$,it will have a maximum at a wavelength:

A
$4\lambda_0$
B
$2\lambda_0$
C
$\lambda_0/2$
D
$\lambda_0/4$

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2 Thermal Properties of Matter: Heat Transfer

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Spectral Emissive Power and Wien's Displacement Law

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The radiation energy density per unit wavelength at a temperature $T$ has a maximum at a wavelength $\lambda_0$. At temperature $2T$,it will have a maximum at a wavelength:

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