The radii of two cylinders are in the ratio 3 | vedclass

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(C) Let the radii of the two cylinders be $r_1$ and $r_2$,and their heights be $h_1$ and $h_2$.Given that $r_1:r_2 = 3:2$ and $h_1:h_2 = 8:11$.The vol

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$18:11$

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(C) Let the radii of the two cylinders be $r_1$ and $r_2$,and their heights be $h_1$ and $h_2$.Given that $r_1:r_2 = 3:2$ and $h_1:h_2 = 8:11$.The volume of a cylinder is given by the formula $V = \pi r^2 h$.The ratio of the volumes of the two cylinders is $\frac{V_1}{V_2} = \frac{\pi r_1^2 h_1}{\pi r_2^2 h_2} = \left(\frac{r_1}{r_2}ight)^2 	imes \left(\frac{h_1}{h_2}ight)$.Substituting the given values: $\frac{V_1}{V_2} = \left(\frac{3}{2}ight)^2 	imes \left(\frac{8}{11}ight) = \frac{9}{4} 	imes \frac{8}{11}$.Calculating the result: $\frac{9 	imes 8}{4 	imes 11} = \frac{72}{44} = \frac{18}{11}$.Thus,the ratio of their volumes is $18:11$.

The radii of two cylinders are in the ratio $3:2$ and their heights are in the ratio $8:11$. The ratio of their volumes is....... .

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