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(C) Let the diameter of the first circle be $d_1 = 36 \, cm$ and the diameter of the second circle be $d_2 = 20 \, cm$.Circumference of the first circ

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$28$

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(C) Let the diameter of the first circle be $d_1 = 36 \, cm$ and the diameter of the second circle be $d_2 = 20 \, cm$.Circumference of the first circle $C_1 = \pi d_1 = 36 \pi \, cm$.Circumference of the second circle $C_2 = \pi d_2 = 20 \pi \, cm$.Let the diameter of the new circle be $D$ and its circumference be $C$.According to the problem,$C = C_1 + C_2$.$\pi D = 36 \pi + 20 \pi$.$\pi D = 56 \pi$.$D = 56 \, cm$.The radius of the new circle is $r = \frac{D}{2} = \frac{56}{2} = 28 \, cm$.

The radius of a circle whose circumference is equal to the sum of the circumferences of the two circles of diameters $36 \, cm$ and $20 \, cm$ is (in $cm$)

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