The radius of a circular ground is 56 , m. In | vedclass

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(A) The radius of the outer circle $(R)$ is $56 \, m$.The width of the road is $7 \, m$.The radius of the inner circle $(r)$ is $R - 	ext{width} = 56

Vedclass · Accepted Answer

$2310$

Vedclass · Answer

(A) The radius of the outer circle $(R)$ is $56 \, m$.The width of the road is $7 \, m$.The radius of the inner circle $(r)$ is $R - 	ext{width} = 56 \, m - 7 \, m = 49 \, m$.The area of the road is the difference between the area of the outer circle and the area of the inner circle.Area of road $= \pi R^2 - \pi r^2 = \pi(R^2 - r^2) = \pi(R - r)(R + r)$.Substituting the values: $	ext{Area} = \frac{22}{7} 	imes (56 - 49) 	imes (56 + 49)$.$	ext{Area} = \frac{22}{7} 	imes 7 	imes 105$.$	ext{Area} = 22 	imes 105 = 2310 \, m^2$.

The radius of a circular ground is $56 \, m$. Inside it, a road of width $7 \, m$ runs all along its boundary. Find the area of this road in $m^2$.

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