The random variable $X$ has a probability distribution $P(X)$ of the following form,where $k$ is some number:
$P(X) = \begin{cases} k, & \text{if } x=0 \\ 2k, & \text{if } x=1 \\ 3k, & \text{if } x=2 \\ 0, & \text{otherwise} \end{cases}$
Determine the value of $k$.
$P(X) = \begin{cases} k, & \text{if } x=0 \\ 2k, & \text{if } x=1 \\ 3k, & \text{if } x=2 \\ 0, & \text{otherwise} \end{cases}$
Determine the value of $k$.
- A$1/6$
- B$1/3$
- C$1/2$
- D$1$
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DifficultMHT CET 2026
View SolutionIf the p.m.f. of a random variable $X$ is given by the following table,then the standard deviation of $X$ is (given $p+q=1$):
$x$ $0$ $1$ $2$ $P(X=x)$ $q^2$ $2pq$ $p^2$
| $x$ | $0$ | $1$ | $2$ |
|---|---|---|---|
| $P(X=x)$ | $q^2$ | $2pq$ | $p^2$ |
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