The range of the function $f(x)=-\sqrt{5-6x-x^2}$ is

If the domain of the function $f(x) = \sqrt{\log_{0.6} (\left| \frac{2x-5}{x^2-4} \right|)}$ is $(-\infty, a] \cup \{b\} \cup [c, d) \cup (e, \infty)$, then the value of $a+b+c+d+e$ is ————

Let $A = \{-4, -2, -1, 0, 3, 5\}$ and $f: A \rightarrow R$ be defined by $f(x) = \begin{cases} 3x - 1 & \text{for } x > 3 \\ x^2 + 1 & \text{for } -3 \leq x \leq 3 \\ 2x - 3 & \text{for } x < -3 \end{cases}$. Then the range of $f$ is

If $f$ is a real-valued function from $A$ onto $B$ defined by $f(x) = \frac{1}{\sqrt{|x - |x||}}$, then $A \cap B = $

The domain of the function $f(x) = \sqrt{\log_{0.5} x!}$ is

The function $f(x) = \frac{\sec^{-1}x}{\sqrt{x - [x]}}$,where $[.]$ denotes the greatest integer less than or equal to $x$,is defined for all $x$ belonging to: