The range of the function $f(x) = \frac{x + 2}{|x + 2|}$ is

The domain of the definition of the function $f(x) = \sqrt{\frac{4 - x^2}{[x] + 2}}$ is (where $[.] \rightarrow \text{G.I.F.}$)

If $f:[2, \infty) \rightarrow B$ defined by $f(x)=x^2-4x+5$ is a bijection, then $B$ is equal to

Given $f(x) = \frac{1}{2} - \tan^{-1}\left(\frac{\pi x}{2}\right)$ for $-1 < x < 1$ and $g(x) = \sqrt{3 + 4x - 4x^2}$. Find the domain of $(f + g)$.

The domain of the function $f(x) = \sqrt{\log_{0.5} x!}$ is

If the domain of the function $f(x) = \log_7(1 - \log_4(x^2 - 9x + 18))$ is $(\alpha, \beta) \cup (\gamma, \delta)$,then $\alpha + \beta + \gamma + \delta$ is equal to