The rates of diffusion of SO_2, CO_2, PCl_3 a | vedclass

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Question

(D) According to Graham's Law of diffusion, the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its molar mass $(M)$.

Vedclass · Accepted Answer

$CO_2 > SO_2 > SO_3 > PCl_3$

Vedclass · Answer

(D) According to Graham's Law of diffusion, the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its molar mass $(M)$.$r \propto \frac{1}{\sqrt{M}}$Calculate the molar masses of the given gases:$M(CO_2) = 12 + 2 	imes 16 = 44 \ g/mol$$M(SO_2) = 32 + 2 	imes 16 = 64 \ g/mol$$M(SO_3) = 32 + 3 	imes 16 = 80 \ g/mol$$M(PCl_3) = 31 + 3 	imes 35.5 = 137.5 \ g/mol$Since the rate of diffusion is inversely proportional to the square root of the molar mass, the gas with the lowest molar mass will have the highest rate of diffusion.The order of molar masses is: $CO_2 (44) Therefore, the order of rates of diffusion is: $CO_2 > SO_2 > SO_3 > PCl_3$.Hence, option $(D)$ is correct.

The rates of diffusion of $SO_2$, $CO_2$, $PCl_3$ and $SO_3$ are in the following order:

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