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Question

(A) Let the speed of the bike be $15x$ and the speed of the train be $27x$.The speed of the bus is calculated as $	ext{Speed} = \frac{	ext{Distance}

Vedclass · Accepted Answer

$756$

Vedclass · Answer

(A) Let the speed of the bike be $15x$ and the speed of the train be $27x$.The speed of the bus is calculated as $	ext{Speed} = \frac{	ext{Distance}}{	ext{Time}} = \frac{720 \, km}{9 \, hours} = 80 \, km/hr$.According to the problem,the speed of the bike is three-fourths the speed of the bus:$15x = \frac{3}{4} 	imes 80$$15x = 60$$x = 4$.Now,calculate the speed of the train:$	ext{Speed of train} = 27x = 27 	imes 4 = 108 \, km/hr$.The distance covered by the train in $7 \, hours$ is:$	ext{Distance} = 	ext{Speed} 	imes 	ext{Time} = 108 \, km/hr 	imes 7 \, hours = 756 \, km$.

The ratio between the speed of a bike and a train is $15:27$ respectively. Also,a bus covers a distance of $720 \, km$ in $9 \, hours$. The speed of the bike is three-fourths the speed of the bus. How much distance will the train cover in $7 \, hours$? (in $km$)

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