The ratio of angular momentum overrightarrow{ | vedclass

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(B) The magnetic dipole moment $\overrightarrow{m}_{	ext{orb}}$ of an electron revolving in a circular orbit is given by $\overrightarrow{m}_{	ext{o

Vedclass · Accepted Answer

$\frac{2m}{e}$

Vedclass · Answer

(B) The magnetic dipole moment $\overrightarrow{m}_{	ext{orb}}$ of an electron revolving in a circular orbit is given by $\overrightarrow{m}_{	ext{orb}} = -\frac{e}{2m} \overrightarrow{L}$,where $\overrightarrow{L}$ is the orbital angular momentum of the electron.Taking the magnitude of both sides,we have $m_{	ext{orb}} = \frac{e}{2m} L$.Therefore,the ratio of angular momentum $L$ to the magnetic dipole moment $m_{	ext{orb}}$ is given by $\frac{L}{m_{	ext{orb}}} = \frac{2m}{e}$.

The ratio of angular momentum $\overrightarrow{L}$ of an electron to the magnetic dipole moment $\overrightarrow{m}_{\text{orb}}$ is (where $m$ is the mass of the electron and $e$ is the charge on the electron).

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