What is the magnetic moment of an orbiting electron in a simple hydrogen atom? Assume $e=$ charge of electron,$m_e=$ mass of electron,and $\vec{L}=$ orbital angular momentum of the electron.

  • A
    $\vec{\mu}=\left(\frac{e}{m_e}\right) \vec{L}$
  • B
    $\vec{\mu}=-\left(\frac{e}{2 m_e}\right) \vec{L}$
  • C
    $\vec{\mu}=\left(\frac{2 e}{m_e}\right) \vec{L}$
  • D
    $\vec{\mu}=\left(\frac{e}{4 m_e}\right) \vec{L}$

Explore More

Similar Questions

An electron $(e)$ is revolving in a circular orbit of radius $r$ in a hydrogen atom. The angular momentum of the electron is (where $M$ is the magnetic dipole moment associated with it and $m$ is the mass of the electron).

$A$ particle of charge '$q$' and mass '$m$' moves in a circular orbit of radius '$r$' with angular speed '$\omega$'. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends upon

Obtain an expression for the orbital magnetic moment of an electron rotating about the nucleus in an atom and explain the gyromagnetic ratio.

Define Bohr magneton using Bohr's first hypothesis.

Difficult
View Solution

$A$ particle of charge '$q$' and mass '$m$' moves in a circular orbit of radius '$r$' with angular speed '$\omega$'. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo