$A$ particle of charge '$q$' and mass '$m$' moves in a circular orbit of radius '$r$' with angular speed '$\omega$'. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends upon

What is the gyromagnetic ratio? Give its magnitude.

The ratio of angular momentum $\overrightarrow{L}$ of an electron to the magnetic dipole moment $\overrightarrow{m}_{\text{orb}}$ is (where $m$ is the mass of the electron and $e$ is the charge on the electron).

The gyromagnetic ratio and Bohr magneton are given respectively by [Given $\rightarrow e=$ charge on electron,$m=$ mass of electron,$h=$ Planck's constant].

$A$ model for quantized motion of an electron in a uniform magnetic field $B$ states that the flux passing through the orbit of the electron is $n(h / e)$ where $n$ is an integer,$h$ is Planck's constant and $e$ is the magnitude of electron's charge. According to the model,the magnetic moment of an electron in its lowest energy state will be ($m$ is the mass of the electron).

The gyromagnetic ratio of an electron is equal to . . . . . . times the specific charge of an electron.