The ratio of radii of 2 right circular cylind | vedclass

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(A) Let the radii of the two cylinders be $r_1$ and $r_2$,and their heights be $h_1$ and $h_2$ respectively.Given,the ratio of radii $r_1 : r_2 = 2 :

Vedclass · Accepted Answer

$5:6$

Vedclass · Answer

(A) Let the radii of the two cylinders be $r_1$ and $r_2$,and their heights be $h_1$ and $h_2$ respectively.Given,the ratio of radii $r_1 : r_2 = 2 : 3$ and the ratio of heights $h_1 : h_2 = 5 : 4$.The curved surface area $(CSA)$ of a cylinder is given by the formula $CSA = 2 \pi r h$.The ratio of the curved surface areas of the two cylinders is $\frac{CSA_1}{CSA_2} = \frac{2 \pi r_1 h_1}{2 \pi r_2 h_2}$.Simplifying this,we get $\frac{CSA_1}{CSA_2} = \frac{r_1}{r_2} 	imes \frac{h_1}{h_2}$.Substituting the given ratios: $\frac{CSA_1}{CSA_2} = \frac{2}{3} 	imes \frac{5}{4} = \frac{10}{12} = \frac{5}{6}$.Thus,the ratio of their curved surface areas is $5:6$.

The ratio of radii of $2$ right circular cylinders is $2:3$ and their heights are in the ratio $5:4$. The ratio of their curved surface area is

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