The ratio of the ages of $Ram$ and $Rahim, 10$ years ago was $1:3$. The ratio of their ages $5$ years hence will be $2:3$. Then the ratio of their present ages is:

The ratio of $A$'s and $B$'s ages is $4:5.$ If the difference between the present age of $A$ and $B$'s age $5$ years hence is $3,$ then what is the sum of the present ages of $A$ and $B$ (in years)?

$A$ father's age is three times the sum of the ages of his two children,but $20 \, \text{years}$ hence his age will be equal to the sum of their ages. Then,the father's age is (in $\text{years}$)

$3 \text{ years}$ ago,the average age of a family of $5$ members was $17 \text{ years}$. $A$ baby having been born,the average age of the family is the same today. What is the age of the child? (in $\text{years}$)

The ratio between the present ages of $P$ and $Q$ is $5: 7$. If the difference between $Q$'s present age and $P$'s age after $6$ $years$ is $2$,what is the sum of ages of $P$ and $Q$ at present? (in $years$)

The age of a father is three times that of his son. After $5$ years,double the father's age will be five times the son's age. The present age of the father and son (in $years$) is: