The ratio of the density of oxygen nucleus $\left({ }_{8}^{16} O \right)$ and helium nucleus $\left({ }_{2}^{4} He \right)$ is (in $:1$)

  • A
    $4$
  • B
    $8$
  • C
    $1$
  • D
    $2$

Explore More

Similar Questions

From the relation $R = R_{0} A^{1/3}$,where $R_{0}$ is a constant and $A$ is the mass number of a nucleus,show that the nuclear matter density is nearly constant (i.e.,independent of $A$).

The ratio of the density of oxygen nucleus $(_{8}^{16}O)$ and helium nucleus $(_{2}^{4}He)$ is (in $: 1$)

$A$ nucleus at rest splits into two nuclear parts having radii in the ratio $1:2$. Their velocities are in the ratio: (in $:1$)

$A$ nucleus (of nuclear density $\rho$) disintegrates into two daughter nuclei with masses in the ratio $8 : 27$. The density of the smaller nucleus is

The nuclei ${ }_{6} C^{13}$ and ${ }_{7} N^{14}$ can be described as

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo