The ratio of the molar amounts of H_2S needed | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The precipitation reactions are:$Cd^{2+} + H_2S \rightarrow CdS + 2H^+$$Cu^{2+} + H_2S \rightarrow CuS + 2H^+$For $Cd(NO_3)_2$:$Moles = Molarity \

Vedclass · Accepted Answer

$2:1$

Vedclass · Answer

(B) The precipitation reactions are:$Cd^{2+} + H_2S ightarrow CdS + 2H^+$$Cu^{2+} + H_2S ightarrow CuS + 2H^+$For $Cd(NO_3)_2$:$Moles = Molarity 	imes Volume = 1 \ M 	imes 0.020 \ L = 0.020 \ mol = 20 \ mmol$.Since the stoichiometry is $1:1$,$20 \ mmol$ of $H_2S$ is required.For $CuSO_4$:$Moles = Molarity 	imes Volume = 0.5 \ M 	imes 0.020 \ L = 0.010 \ mol = 10 \ mmol$.Since the stoichiometry is $1:1$,$10 \ mmol$ of $H_2S$ is required.The ratio of $H_2S$ required is $20:10 = 2:1$.

The ratio of the molar amounts of $H_2S$ needed to precipitate the metal ions from $20 \ mL$ each of $1 \ M \ Cd(NO_3)_2$ and $0.5 \ M \ CuSO_4$ is

Similar Questions

If $5.85 \ g$ of sodium chloride is added to water to make a $500 \ mL$ solution,what is the molarity of the sodium chloride solution (in $M$)? (Molar mass $= 58.5 \ g/mol$)

The chloride of a metal has the formula $MCl_3$. The formula of its phosphate will be

What is the volume in $dm^3$ occupied by $3 \ mol$ of ammonia gas at $STP$?

The active mass of $64 \ g$ of $HI$ in a $2 \ L$ flask is......

$x$ grams of calcium carbonate was completely burnt in air. The weight of the solid residue formed is $28 \,g$. What is the value of $x$ (in grams)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module