The reaction 2SO_2 + O_2 rightleftharpoons 2S | vedclass

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Question

(B) The given reaction is $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$; $\Delta H = -ve$. Since $\Delta H$ is negative,the reaction is exothermic.

Vedclass · Accepted Answer

Low temperature,high pressure

Vedclass · Answer

(B) The given reaction is $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$; $\Delta H = -ve$. Since $\Delta H$ is negative,the reaction is exothermic. According to Le Chatelier's principle,for an exothermic reaction,a low temperature favours the forward reaction. Regarding pressure,the number of moles of gaseous reactants is $2 + 1 = 3$,and the number of moles of gaseous products is $2$. Since the number of moles decreases in the forward direction,high pressure favours the forward reaction. Therefore,the reaction is favoured by low temperature and high pressure.

The reaction $2SO_2 + O_2 \rightleftharpoons 2SO_3$; $\Delta H = -ve$ is favoured by

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