The reaction of hydrogen and iodine monochloride is given as :
$H_{2(g)} + 2ICl_{(g)} \rightarrow 2HCl_{(g)} + I_{2(g)}$
This reaction is of first order with respect to $H_{2(g)}$ and $ICl_{(g)}$. The following mechanisms were proposed:
Mechanism $A$ :
$H_{2(g)} + 2ICl_{(g)} \rightarrow 2HCl_{(g)} + I_{2(g)}$
Mechanism $B$ :
$H_{2(g)} + ICl_{(g)} \rightarrow HCl_{(g)} + HI_{(g)}$ ; (slow)
$HI_{(g)} + ICl_{(g)} \rightarrow HCl_{(g)} + I_{2(g)}$ ; (fast)
Which of the above mechanism$(s)$ can be consistent with the given information about the reaction?

  • A
    $A$ and $B$ both
  • B
    Neither $A$ nor $B$
  • C
    $A$ only
  • D
    $B$ only

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The reaction between $A$ and $B$ is first order with respect to $A$ and zero order with respect to $B$. Fill in the blanks in the following table:
Experiment $[A] / mol \, L^{-1}$ $[B] / mol \, L^{-1}$ Initial rate / $mol \, L^{-1} \, min^{-1}$
$I$ $0.1$ $0.1$ $2.0 \times 10^{-2}$
$II$ $-$ $0.2$ $4.0 \times 10^{-2}$
$III$ $0.4$ $0.4$ $-$
$IV$ $-$ $0.2$ $2.0 \times 10^{-2}$

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The rate constant for the reaction,$2N_2O_5 \to 4NO_2 + O_2$ is $3.0 \times 10^{-4} \ s^{-1}$. If the reaction starts with $1.0 \ mol \ L^{-1}$ of $N_2O_5$,calculate the rate of formation of $NO_2$ at the moment when the concentration of $O_2$ is $0.1 \ mol \ L^{-1}$.

What will be the overall order of a reaction for which the rate expression is given as $Rate = K[A]^{\frac{1}{2}}[B]^{\frac{3}{2}}$?

The mechanism for the reaction is given below:
$2P + Q \to S + T$
$P + Q \to R + S$ (slow)
$P + R \to T$ (fast)
The rate law expression for the reaction is:

$A_2 + 2 \, B \to 2 \, AB$
$[A_2]$ $[B]$ $-d[A_2]/dt$
$0.1$ $0.2$ $1 \times 10^{-2} \, M \, s^{-1}$
$0.2$ $0.2$ $2 \times 10^{-2} \, M \, s^{-1}$
$0.2$ $0.4$ $8 \times 10^{-2} \, M \, s^{-1}$

The order of reaction with respect to $A_2$ and $B$ are respectively:

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