The reaction of propane with bromine in the p | vedclass

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(B) The reaction of propane $(CH_3-CH_2-CH_3)$ with bromine $(Br_2)$ in the presence of $UV$ light is a free radical substitution reaction.Bromination

Vedclass · Accepted Answer

$2-$Bromopropane

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(B) The reaction of propane $(CH_3-CH_2-CH_3)$ with bromine $(Br_2)$ in the presence of $UV$ light is a free radical substitution reaction.Bromination is highly selective compared to chlorination.The stability of the intermediate free radical determines the major product.Secondary $(2^{\circ})$ free radicals are more stable than primary $(1^{\circ})$ free radicals.Propane has two primary carbons and one secondary carbon.Abstraction of a hydrogen atom from the secondary carbon leads to the formation of a $2^{\circ}$ propyl radical $(CH_3-\dot{C}H-CH_3)$,which is more stable.Therefore,the reaction predominantly forms $2-$bromopropane $(CH_3-CH(Br)-CH_3)$.

The reaction of propane with bromine in the presence of $UV$ light predominantly forms

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