The refractive index of water in a biology la | vedclass

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(B) The refractive index $\mu$ is given by $\mu = 1.33 + \frac{0.002}{\lambda^2}$.Since $\mu$ is inversely proportional to the square of the wavelengt

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shallower for the blue pieces than the orange ones

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(B) The refractive index $\mu$ is given by $\mu = 1.33 + \frac{0.002}{\lambda^2}$.Since $\mu$ is inversely proportional to the square of the wavelength $\lambda$,smaller wavelengths correspond to a higher refractive index.The order of wavelengths is $\lambda_{	ext{blue}} Therefore,the refractive index follows the order $\mu_{	ext{blue}} > \mu_{	ext{orange}}$.The apparent depth $d'$ is related to the real depth $d$ and refractive index $\mu$ by the formula $d' = \frac{d}{\mu}$.Since $d$ is constant for all pieces at the bottom,$d' \propto \frac{1}{\mu}$.Because $\mu_{	ext{blue}} > \mu_{	ext{orange}}$,it follows that $d'_{	ext{blue}} Thus,the image of the blue pieces appears shallower than that of the orange pieces.

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