The Reimer-Tiemann reaction involves the form | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The Reimer-Tiemann reaction is a chemical reaction used for the ortho-formylation of phenols. In this reaction,phenol reacts with chloroform $(CHC

Vedclass · Accepted Answer

$X$: Salicylaldehyde,$Y$: o-dichloromethyl phenoxide ion

Vedclass · Answer

(A) The Reimer-Tiemann reaction is a chemical reaction used for the ortho-formylation of phenols. In this reaction,phenol reacts with chloroform $(CHCl_3)$ in the presence of an aqueous base like $KOH$ to form salicylaldehyde $(X)$. The reaction proceeds through the formation of a dichlorocarbene $(:CCl_2)$ intermediate,which attacks the phenoxide ion to form an ortho-dichloromethyl substituted phenoxide intermediate $(Y)$. This intermediate $Y$ then undergoes hydrolysis to yield the final product,salicylaldehyde $(X)$.

The Reimer-Tiemann reaction involves the formation of $X$ from phenol through the intermediate $Y$. What are $X$ and $Y$?

Similar Questions

The correct sequence of reactions to convert $p$-nitrophenol into quinol involves

The most suitable method for the separation of a $1:1$ mixture of $o-$ and $p-$ nitrophenols is:

Which of the following will be most easily attacked by an electrophile?

The major product of the following reaction is:

The ascending order of acidity of the $-OH$ group in the following compounds is:
$A$. $Bu-OH$
$B$. $p$-nitrophenol
$C$. $p$-methoxyphenol
$D$. Phenol
$E$. $2,4$-dinitrophenol
Choose the correct answer from the options given below:

Vedclass Test Series

Exam Paper Generator

Online Exam Module