The relation R defined on the set A = {1, 2, | vedclass

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(D) The relation $R$ is defined on set $A = \{1, 2, 3, 4, 5\}$ as $R = \{(x, y) : |x^2 - y^2| < 16\}$.We check all possible pairs $(x, y)$ from $A 	i

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None of the above

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(D) The relation $R$ is defined on set $A = \{1, 2, 3, 4, 5\}$ as $R = \{(x, y) : |x^2 - y^2| We check all possible pairs $(x, y)$ from $A 	imes A$ such that $|x^2 - y^2| For $x=1$: $|1-1|=0  16$. Pairs: $(1,1), (1,2), (1,3), (1,4)$.For $x=2$: $|4-1|=3  16$. Pairs: $(2,1), (2,2), (2,3), (2,4)$.For $x=3$: $|9-1|=8 For $x=4$: $|16-1|=15 For $x=5$: $|25-1|=24 > 16, |25-4|=21 > 16, |25-9|=16 
otThe set $R$ contains many more elements than those listed in options $A, B,$ or $C$. Thus,the correct option is $D$.

The relation $R$ defined on the set $A = \{1, 2, 3, 4, 5\}$ by $R = \{(x, y) : |x^2 - y^2| < 16\}$ is given by

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