The resistance of $\frac{1}{10} \ M$ solution is $2.5 \times 10^3 \ \Omega$. What is the molar conductivity of the solution? (Cell constant $= 1.25 \ cm^{-1}$)

The resistance of a $0.2 \ M$ solution of an electrolyte is $30 \ \Omega$ and conductivity is $1.2 \ S \ m^{-1}$. What is the value of the cell constant (in $cm^{-1}$)?

Given that $\Lambda_{m}^{\infty} = 133.4 \, S \, cm^{2} \, mol^{-1} (AgNO_{3})$; $\Lambda_{m}^{\infty} = 149.9 \, S \, cm^{2} \, mol^{-1} (KCl)$ and $\Lambda_{m}^{\infty} = 144.9 \, S \, cm^{2} \, mol^{-1} (KNO_{3})$,the molar conductivity at infinite dilution for $AgCl$ is $....... \, S \, cm^{2} \, mol^{-1}$.

$\Lambda _m^\circ$ for $NaCl$,$HCl$ and $NaAc$ are $126.4$,$425.9$ and $91.0 \ S \ cm^2 \ mol^{-1}$ respectively. Calculate $\Lambda _m^\circ$ for $HAc$.

If $ᴧ^{0} CH_{3}COONa = 91 \ S \ cm^{2} \ mol^{-1}$ and $ᴧ^{0} HCl = 462.2 \ S \ cm^{2} \ mol^{-1}$,then what value is required to calculate $ᴧ^{0} CH_{3}COOH$?

Calculate the molar conductivity of $NH_4OH$ at infinite dilution,given that the molar conductivities of $Ba(OH)_2$,$BaCl_2$,and $NH_4Cl$ are $523.28$,$280.0$,and $129.8 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.