The resistance of the platinum wire of a plat | vedclass

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(C) Given:Resistance at ice point $(R_0)$ = $5 \Omega$ at $	heta_0 = 0^{\circ} C$Resistance at steam point $(R_{100})$ = $5.23 \Omega$ at $	heta_{10

Vedclass · Accepted Answer

$345.65$

Vedclass · Answer

(C) Given:Resistance at ice point $(R_0)$ = $5 \Omega$ at $	heta_0 = 0^{\circ} C$Resistance at steam point $(R_{100})$ = $5.23 \Omega$ at $	heta_{100} = 100^{\circ} C$Resistance in hot bath $(R_{	heta})$ = $5.795 \Omega$The formula for temperature in a platinum resistance thermometer is:$	heta = \frac{R_{	heta} - R_0}{R_{100} - R_0} 	imes 100^{\circ} C$Substituting the values:$	heta = \frac{5.795 - 5}{5.23 - 5} 	imes 100^{\circ} C$$	heta = \frac{0.795}{0.23} 	imes 100^{\circ} C$$	heta = 3.4565 	imes 100^{\circ} C$$	heta = 345.65^{\circ} C$Therefore,the temperature of the bath is $345.65^{\circ} C$.

The resistance of the platinum wire of a platinum resistance thermometer at an ice point is $5 \Omega$ and at steam point is $5.23 \Omega$. When the thermometer is inserted in a hot bath,the resistance of a platinum wire is $5.795 \Omega$. Calculate the temperature of the bath. (in $^{\circ} C$)

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