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(C) The given circuit consists of a $NOR$ gate followed by a $NOT$ gate.$1$. The first gate is a $NOR$ gate with inputs $A$ and $B$. The output of the

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$OR$, $A + B$

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(C) The given circuit consists of a $NOR$ gate followed by a $NOT$ gate.$1$. The first gate is a $NOR$ gate with inputs $A$ and $B$. The output of the $NOR$ gate is $C = \overline{A + B}$.$2$. The second gate is a $NOT$ gate (inverter) which takes the input $C$ and produces the output $Y = \overline{C}$.$3$. Substituting the value of $C$, we get $Y = \overline{(\overline{A + B})}$.$4$. According to the law of double negation, $\overline{\overline{X}} = X$. Therefore, $Y = A + B$.$5$. $A$ circuit that performs the operation $Y = A + B$ is an $OR$ gate.Thus, the resultant gate is an $OR$ gate and its Boolean expression is $A + B$.

The resultant gate and its Boolean expression in the given circuit is

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