The roots of the quadratic equation ldots ldo | vedclass

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Question

(D) quadratic equation with roots $\alpha$ and $\beta$ is given by the formula: $x^{2} - (\alpha + \beta)x + (\alpha \cdot \beta) = 0$.Given roots are

Vedclass · Accepted Answer

$x^{2}-x-20=0$

Vedclass · Answer

(D) quadratic equation with roots $\alpha$ and $\beta$ is given by the formula: $x^{2} - (\alpha + \beta)x + (\alpha \cdot \beta) = 0$.Given roots are $\alpha = -4$ and $\beta = 5$.Sum of roots: $\alpha + \beta = -4 + 5 = 1$.Product of roots: $\alpha \cdot \beta = (-4) 	imes 5 = -20$.Substituting these values into the formula: $x^{2} - (1)x + (-20) = 0$.This simplifies to: $x^{2} - x - 20 = 0$.Therefore,the correct option is $D$.

The roots of the quadratic equation $\ldots \ldots \ldots \ldots$ are $-4$ and $5$.

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