The sequence of reagents which convert p-meth | vedclass

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Question

(C) The conversion of $p-$methyl aniline to $p-$methyl benzoic acid involves the following steps:$1$. Diazotization: $p-$methyl aniline reacts with $N

Vedclass · Accepted Answer

$NaNO_2 + HCl / 273 \ K ; CuCN / KCN ; H_3O^{+}$

Vedclass · Answer

(C) The conversion of $p-$methyl aniline to $p-$methyl benzoic acid involves the following steps:$1$. Diazotization: $p-$methyl aniline reacts with $NaNO_2 + HCl$ at $273 \ K$ to form $p-$methyl benzene diazonium chloride.$2$. Sandmeyer reaction: The diazonium salt reacts with $CuCN / KCN$ to form $p-$methyl benzonitrile.$3$. Hydrolysis: The nitrile group is hydrolyzed using $H_3O^{+}$ to form $p-$methyl benzoic acid.Thus,the correct sequence is $NaNO_2 + HCl / 273 \ K ; CuCN / KCN ; H_3O^{+}$.

The sequence of reagents which convert $p-$methyl aniline to $p-$methyl benzoic acid are

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