The set {x in R: cos 2x + 2 cos^2 x = 2} is e | vedclass

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(B) Given equation is $\cos 2x + 2 \cos^2 x = 2$.Using the identity $\cos 2x = 2 \cos^2 x - 1$,we get:$(2 \cos^2 x - 1) + 2 \cos^2 x = 2$$4 \cos^2 x -

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$\{n\pi \pm \frac{\pi}{6}: n \in Z\}$

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(B) Given equation is $\cos 2x + 2 \cos^2 x = 2$.Using the identity $\cos 2x = 2 \cos^2 x - 1$,we get:$(2 \cos^2 x - 1) + 2 \cos^2 x = 2$$4 \cos^2 x - 1 = 2$$4 \cos^2 x = 3$$\cos^2 x = \frac{3}{4}$$\cos x = \pm \frac{\sqrt{3}}{2}$For $\cos x = \frac{\sqrt{3}}{2}$,$x = 2n\pi \pm \frac{\pi}{6}$.For $\cos x = -\frac{\sqrt{3}}{2}$,$x = 2n\pi \pm \frac{5\pi}{6}$.Combining these,the general solution is $x = n\pi \pm \frac{\pi}{6}$ for $n \in Z$.

The set $\{x \in R: \cos 2x + 2 \cos^2 x = 2\}$ is equal to

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