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(A) $1$. The shaded region is bounded by the lines $x=0$ ($Y$-axis),$y=0$ ($X$-axis),$x=5$,$y=3$,and the line passing through $(0,0)$ and $(3,3)$.$2$.

Vedclass · Accepted Answer

$x, y \geq 0 ; x-y \geq 0 ; x \leq 5 ; y \leq 3$

Vedclass · Answer

(A) $1$. The shaded region is bounded by the lines $x=0$ ($Y$-axis),$y=0$ ($X$-axis),$x=5$,$y=3$,and the line passing through $(0,0)$ and $(3,3)$.$2$. The line passing through $(0,0)$ and $(3,3)$ has the equation $y=x$,which can be written as $x-y=0$. Since the shaded region lies below this line,the constraint is $x-y \geq 0$.$3$. The vertical line $x=5$ bounds the region on the right,so $x \leq 5$.$4$. The horizontal line $y=3$ bounds the region on the top,so $y \leq 3$.$5$. Since the region is in the first quadrant,$x \geq 0$ and $y \geq 0$.$6$. Combining these,the constraints are $x, y \geq 0, x-y \geq 0, x \leq 5, y \leq 3$.

The shaded part of the given figure indicates the feasible region. Then the constraints are

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