The shaded region given in the figure represe | vedclass

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(A) $1$. Observe the vertical line $x = 3$. The shaded region lies to the left of this line,which corresponds to $x \leq 3$. Since the line is solid,t

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$x \leq 3$ and $y < 1$

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(A) $1$. Observe the vertical line $x = 3$. The shaded region lies to the left of this line,which corresponds to $x \leq 3$. Since the line is solid,the inequality includes the boundary.$2$. Observe the horizontal line $y = 1$. The shaded region lies below this line,which corresponds to $y $3$. Combining these,the shaded region represents the system of inequalities $x \leq 3$ and $y < 1$.

The shaded region given in the figure represents the $\ldots \ldots \ldots$ inequality.

Similar Questions

The shaded region shown in the figure is given by the inequations:

Solve the following system of inequalities graphically: $x \geq 0, y \geq 0, 5x + 3y \leq 15, 4x + 5y \leq 20$.

Solve the following system of inequalities graphically: $x+y \geq 4, 2x-y > 0$.

The shaded region in the following figure represents the solution set of:

The shaded region in the following figure is the solution set of the inequations:

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