The shape of SO_4^{2-} ion is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The central sulfur atom in $SO_4^{2-}$ has $6$ valence electrons. It forms $4$ bonds with oxygen atoms. The steric number is calculated as $\frac{

Vedclass · Accepted Answer

Tetrahedral

Vedclass · Answer

(B) The central sulfur atom in $SO_4^{2-}$ has $6$ valence electrons. It forms $4$ bonds with oxygen atoms. The steric number is calculated as $\frac{1}{2}(V + M - C + A) = \frac{1}{2}(6 + 0 - 0 + 2) = 4$. Since the steric number is $4$,the hybridization is $sp^3$. Therefore,the shape of the $SO_4^{2-}$ ion is tetrahedral.

The shape of $SO_4^{2-}$ ion is

Similar Questions

The bond angle of water is $104.5^{\circ}$ due to

The $XeF_2$ molecule is:

The structure of ammonia is:

Which of the following has a square planar structure?

Which of the following species is non-linear?

Vedclass Test Series

Exam Paper Generator

Online Exam Module