The shortest distance from the origin to a variable point on the sphere $(x-2)^2+(y-3)^2+(z-6)^2=1$ is

  • A
    $5$
  • B
    $6$
  • C
    $7$
  • D
    $8$

Explore More

Similar Questions

$A$ point moves such that the sum of the squares of its distances from two given points remains constant. The locus of the point is

The radius of the circular section of the sphere $|r| = 5$ by the plane $r \cdot (i + j + k) = 3\sqrt{3}$ is

Difficult
View Solution

If $(2, 3, 5)$ is one end of a diameter of the sphere ${x^2} + {y^2} + {z^2} - 6x - 12y - 2z + 20 = 0$,then the coordinates of the other end of the diameter are:

What is the center of the sphere passing through the four points $(0, 0, 0), (0, 2, 0), (1, 0, 0),$ and $(0, 0, 4)$?

The equation ${x^2} + {y^2} + {z^2} = 0$ represents

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo